RIDDLES -- Dimag ki batti jalao

Will there be a collision?

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George is driving 100 ft/sec toward an intersection. He looks to his right, and sees Bill, driving 30 ft/sec toward the same intersection. George foolishly slams on his brakes. If he had kept going 100 ft/sec, he would have been through the intersection long before Bill got there. At the instant that he slams on his brakes, the center of George's car is 125 ft from the intersection, and the center of Bill's car is 150 ft from the intersection. George's brakes give his car an acceleration of -30 ft/sec/sec. Bill never changes his speed. Each car is 13 ft long and 7 ft wide.
Will there be a collision?
 
Bhai..ya to cheating se...meri RIDDLE ka jawaab to kisey ne na diya...manney te oran ki riddle ka jawaab diya tha...I repeat my riddle

"Ek aisa praani batao jo jameen per chal (Daudd) sakta hai , Aasmaan main udd sakta hai and paani main tair sakta hai...."
 
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No collision.....
George reach the intersection after 5/3 sec.. while Bill takes 5 sec...
Dharampalkaswan said:
accel.gif
George is driving 100 ft/sec toward an intersection. He looks to his right, and sees Bill, driving 30 ft/sec toward the same intersection. George foolishly slams on his brakes. If he had kept going 100 ft/sec, he would have been through the intersection long before Bill got there. At the instant that he slams on his brakes, the center of George's car is 125 ft from the intersection, and the center of Bill's car is 150 ft from the intersection. George's brakes give his car an acceleration of -30 ft/sec/sec. Bill never changes his speed. Each car is 13 ft long and 7 ft wide.
Will there be a collision?
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htomar said:
No collision.....
George reach the intersection after 5/3 sec.. while Bill takes 5 sec...
Click to expand...

u r right at answer that is "No collision"...........but i think u did not do the right solution....according to me...when Bill reaches at the possible collision point...George will have crossed it and his car will be 5 ft far along his direction..

because George car travels 140 ft distance in the time taken by the car of Bill for travelling the distance of 140 ft with the constt speed of 30ft/sec which does not meet the collision condition.

for meeting the collision, the distance travelled by George's car(after applying the breaks ) should be between115 ft and 135 ft.
 
Right solution !!

It is right that there will be no collision. The correct solution is as under :
George will zoom right on through the intersection, and will come to a halt 41 2/3 feet beyond the intersection, 1 2/3 seconds before Bill gets there.
How long will it take George to come to a stop?
v(final) = v(initial) - at
0 = 100 - 30t
t = 3 1/3 sec
Where will he end up?
d = vt - ½at²
d = 166 2/3
That's 41 2/3 feet beyond the intersection.
There will be no collision.
sachinnain said:
u r right at answer that is "No collision"...........but i think u did not do the right solution....according to me...when Bill reaches at the possible collision point...George will have crossed it and his car will be 5 ft far along his direction..

because George car travels 140 ft distance in the time taken by the car of Bill for travelling the distance of 140 ft with the constt speed of 30ft/sec which does not meet the collision condition.

for meeting the collision, the distance travelled by George's car(after applying the breaks ) should be between115 ft and 135 ft.
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Devide the money !

Three travelers are sitting around a fire, and are about to eat a meal. One of them has five small loaves of bread, the second has three small loaves of bread. The third has no food, but has eight coins. He offers to pay for some bread. They agree to share the eight loaves equally among the three travelers, and the third traveler will pay eight coins for his share of the eight loaves. All loaves were the same size. The second traveler (who had three loaves) suggests that he be paid three coins, and that the first traveler be paid five coins. The first traveler says that he should get more than five coins. Is he right? How should the money be divided up?
 
Yes.. first traveler is right...he should get more coins...
First traveler got 7 coins and second got 1 coin....
Dharampalkaswan said:
Three travelers are sitting around a fire, and are about to eat a meal. One of them has five small loaves of bread, the second has three small loaves of bread. The third has no food, but has eight coins. He offers to pay for some bread. They agree to share the eight loaves equally among the three travelers, and the third traveler will pay eight coins for his share of the eight loaves. All loaves were the same size. The second traveler (who had three loaves) suggests that he be paid three coins, and that the first traveler be paid five coins. The first traveler says that he should get more than five coins. Is he right? How should the money be divided up?
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each of them got 8/3 loaves....
third traveler paid 8 coins for 8/3 loaves..
price of 8/3 loaves = 8 coins
so price of 1 = 3 coins
first traveler give 5- 8/3=7/3 loaves....so he got 7 coins...
second traveler give 3- 8/3=1/3 .... so he got 1 coin....
Dharampalkaswan said:
You are absolutely right
Tomar Ji. Can you explian your calculation ?
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Who are Banta & Santa?

We are taking one statement from each of eight people. The last two are Santa and Banta, or may be Banta and Santa. Anyway, one of those two is Santa, the other is Banta. See if you can deduce which is Banta and which is Santa:
1. Exactly seven of us are lying.
2. Exactly six of us are lying.
3. Exactly five of us are lying.
4. Yes, exactly five of us are lying.
5. Exactly four of us are lying.
6. Exactly three of us are lying.
7. My name is Santa.
8. My name is Banta.
? ? ? ? ? ? ? ? ? ? ? ?
 
For no. 7 and 8 , either both are true or false....
3 and 4 are same...so leave one from them..lets say no. 3......
Now 1,2,4,5,6 are contradictory...so at least 4 out of them are false....

If only 4 statement are false.... then no. 5 is true..but in this case no. 3 also false..so it is not possible....

If onle 5 statement are false....then 3 nad 4 are true...1,2,5,6 are false and one of 7 and 8 is false...that is not possible bcos 7 and 8 either both true or false..

If only 6 statement are false.....then no.2 is true...1,3,4,5,6 are false and one of 7 and 8. again not possible....

If 7 statement are false....then no. 1 is true...2,3,4,5,6,7 and 8 are false...
If all statement are false....

There are only two possibily either 7 or all statement are false....
In both cases no. 7 and 8 are false...

so No.7 is Banta and no. 8 is Santa.......


Dharampalkaswan said:
We are taking one statement from each of eight people. The last two are Santa and Banta, or may be Banta and Santa. Anyway, one of those two is Santa, the other is Banta. See if you can deduce which is Banta and which is Santa:
1. Exactly seven of us are lying.
2. Exactly six of us are lying.
3. Exactly five of us are lying.
4. Yes, exactly five of us are lying.
5. Exactly four of us are lying.
6. Exactly three of us are lying.
7. My name is Santa.
8. My name is Banta.
? ? ? ? ? ? ? ? ? ? ? ?
Click to expand...
 
There are four people in an adventure race that need to get across a lake. They have a small canoe. The rules say that only the slowest person in the canoe can paddle, only one or two can be in the canoe at a time, and they must all cross in the canoe. From practice, they know that:
Ann can paddle across in 1 minute.
Bill can paddle across in 2 minutes.
Sue can paddle across in 5 minutes.
Mike can paddle across in 10 minutes.
How do they get everyone across the river in the fastest time without breaking the rules?

The answer is first the Mike and Sue will cross the lake mikes gets down and sue paddels back and take bill along with it and cross the lake and sue will stay back and bill paddels back and take the Ann with him and in this all will cross the lake.

other answer is if they are in race then they must have their own conoe to cross the lake.
 
There are five friends. Josh says his birthdate is 31st December 1878. Rick says his birthdate is 14th November 1902, Derik says his birthdate is 12th July 1898, Usha says her birthdate is 29th February 1900, and Mike says his birthdate is 15th May 1904. In which year,will the sum of their ages be equal to a prime number between 175 and 240?

Pls Don't use any search engine, try to solve by yourself only Its a easy one :)
 
Nishantrathi82 said:
There are five friends. Josh says his birthdate is 31st December 1878. Rick says his birthdate is 14th November 1902, Derik says his birthdate is 12th July 1898, Usha says her birthdate is 29th February 1900, and Mike says his birthdate is 15th May 1904. In which year,will the sum of their ages be equal to a prime number between 175 and 240?

Pls Don't use any search engine, try to solve by yourself only Its a easy one :)
Click to expand...


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